将 含嵌套对象和数组的 JSON 字符串解析为 Map

示例代码

    @Test
    public void JsonToComplexMap () {
        // 示例的JSON字符串
        String json = """
                {
                    "person": {
                        "name": "John",
                        "age": 30,
                        "address": {
                            "street": "123 Main St",
                            "city": "New York",
                            "state": "NY"
                        },
                        "hobbies": ["reading", "swimming", "coding"]
                    }
                }
                """;
        // 使用FastJSON2将JSON字符串转换为Map
        Map<String, Object> map = JSON.parseObject(json, Map.class);

        // 输出解析后的对象
        System.out.println(map);
        // 也可以访问具体的键值对
        Map<String, Object> person = (Map<String, Object>) map.get("person");
        System.out.println(person.get("name")); // 输出 John
        System.out.println(person.get("age")); // 输出 30

        // 访问嵌套的地址信息
        Map<String, Object> address = (Map<String, Object>) person.get("address");
        System.out.println(address.get("street")); // 输出 123 Main St
        System.out.println(address.get("city")); // 输出 New York
        System.out.println(address.get("state")); // 输出 NY

        // 访问爱好列表
        List<String> hobbies = (List<String>) person.get("hobbies");
        System.out.println(hobbies); // 输出 [reading, swimming, coding]
    }

输出

{person={"name":"John","age":30,"address":{"street":"123 Main St","city":"New York","state":"NY"},"hobbies":["reading","swimming","coding"]}}
John
30
123 Main St
New York
NY
["reading","swimming","coding"]